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(F)=F^2-4.4F+2
We move all terms to the left:
(F)-(F^2-4.4F+2)=0
We get rid of parentheses
-F^2+F+4.4F-2=0
We add all the numbers together, and all the variables
-1F^2+5.4F-2=0
a = -1; b = 5.4; c = -2;
Δ = b2-4ac
Δ = 5.42-4·(-1)·(-2)
Δ = 21.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.4)-\sqrt{21.16}}{2*-1}=\frac{-5.4-\sqrt{21.16}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.4)+\sqrt{21.16}}{2*-1}=\frac{-5.4+\sqrt{21.16}}{-2} $
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